PIC单片机的BCD码处理程序
#define PAGE  EJECT
  TITLE "BCD Arithmetic Routines : Ver 1.0"
;************************************************
;        BCD Arithmetic Routines
;************************************************
LIST columns=120, WRAP, L=0
include "17c42.h"
CBLOCK 0x20
Lbyte, Hbyte
R2, R1, R0     ;must maintain R2, R1, R0 sequence
count
Num1, Num2
ENDC
;
BCD equ  Num1
Htemp equ  Num1
Ltemp equ  Num2
;
PAGE
ORG 0x0000
;*******************************************************************
;        BCD Arithmetic Test Program
;*******************************************************************
;
main
setf Hbyte
setf Lbyte
;           ; 16 bit binary num = 0xffff
call  B2_BCD_Looped ; after conversion the Decimal Num
;           ; in R0, R1, R2 = 06,55,35
setf Hbyte
setf Lbyte
call  B2_BCD_Straight ; same as above, but straight line code
;
movlw  0x06
movwf R0
movlw  0x55
movwf R1
movlw  0x35
movwf R2    ; setf R0R1R2 = 65535
;
call  BCDtoB    ; after conversion Hbyte = 0xff
;           ; and Lbyte = 0xff
movlw  0x99
movwf Num1
movlw  0x99
movwf Num2    ; setf Num1 = Num2 = 0x99 (max BCD)
;
call  BCDAdd    ; after addition, Num2 = 98
;           ; and Num1 = 01 ( 99+99 = 198)
;
movlw  0x63    ; setf Wreg = 63 hex
call  BinBCD    ; after conversion, BCD = 99
;           ; 63 hex = 99 decimal.
;
self  goto  self
;
PAGE
;*******************************************************************;
;      Binary To BCD Conversion Routine (8 bit)
;
;   This routine converts the 8 bit binary number in the W Reg
; to a 2 digit BCD number in location BCD( compacted BCD Code)
;   The least significant digit is returned in location LSD and
; the most significant digit is returned in location MSD.
;
; Performance :
;     Program Memory:10
;     Clock Cycles  :62(worst case when W = 63 Hex )
;            ( i.e max Decimal number 99 )
;*******************************************************************
;
BinBCD
clrf BCD
again
addlw  -10
btfss  _carry
goto  swapBCD
incf BCD
goto  again
swapBCD
addlw  10
swapf  BCD
iorwf BCD
return
;
PAGE
;********************************************************************
;      Binary To BCD Conversion Routine (16 Bit)
;       (LOOPED Version)
;
;  This routine converts a 16 Bit binary Number to a 5 Digit
; BCD Number.
;
;   The 16 bit binary number is input in locations Hbyte and
; Lbyte with the high byte in Hbyte.
;   The 5 digit BCD number is returned in R0, R1 and R2 with R0
; containing the MSD in its right most nibble.
;
; Performance :
;     Program Memory:32
;     Clock Cycles  :750
;
;*******************************************************************;
;
B2_BCD_Looped
bsf  _fs0
bsf  _fs1    ; set fsr0 for no auto increment
;
bcf  _carry
clrf count
bsf  count,4   ; set count = 16
clrf R0
clrf R1
clrf R2
loop16a
rlcf Lbyte
rlcf Hbyte
rlcf R2
rlcf R1
rlcf R0
;
dcfsnz count
return
adjDEC
movlw  R2    ; load R2 as indirect address ptr
movwf fsr0
call  adjBCD
;
incf fsr0
call  adjBCD
;
incf fsr0
call  adjBCD
;
goto  loop16a
;
adjBCD
movfp  indf0,wreg
addlw  0x03
btfsc  wreg,3    ; test if result > 7
movwf indf0
movfp  indf0,wreg
addlw  0x30
btfsc  wreg,7    ; test if result > 7
movwf indf0   ; save as MSD
return
;
;********************************************************************
;      Binary To BCD Conversion Routine (16 Bit)
;       (Partial Straight Line Version)
;
;  This routine converts a 16 Bit binary Number to a 5 Digit
; BCD Number.
;
;   The 16 bit binary number is input in locations Hbyte and
; Lbyte with the high byte in Hbyte.
;   The 5 digit BCD number is returned in R0, R1 and R2 with R0
; containing the MSD in its right most nibble.
;
; Performance :
;     Program Memory:44
;     Clock Cycles  :572
;
;*******************************************************************;
;
B2_BCD_Straight
bsf  _fs0
bsf  _fs1    ; set fsr0 for no auto increment
;
bcf  _carry
clrf count
bsf  count,4   ; set count = 16
clrf R0
clrf R1
clrf R2
loop16b
rlcf Lbyte
rlcf Hbyte
rlcf R2
rlcf R1
rlcf R0
;
dcfsnz count
return       ; DONE
movlw  R2    ; load R2 as indirect address ptr
movwf  fsr0
; adjustBCD
movfp  indf0,wreg
addlw  0x03
btfsc  wreg,3    ; test if result > 7
movwf  indf0
movfp  indf0,wreg
addlw  0x30
btfsc  wreg,7    ; test if result > 7
movwf  indf0   ; save as MSD
;
incf fsr0
; adjustBCD
movfp  indf0,wreg
addlw  0x03
btfsc  wreg,3    ; test if result > 7
movwf  indf0
movfp  indf0,wreg
addlw  0x30
btfsc  wreg,7    ; test if result > 7
movwf  indf0   ; save as MSD
;
incf fsr0
; adjustBCD
movfp  indf0,wreg
addlw  0x03
btfsc  wreg,3    ; test if result > 7
movwf  indf0
movfp  indf0,wreg
addlw  0x30
btfsc  wreg,7    ; test if result > 7
movwf  indf0   ; save as MSD
;
goto  loop16b
;
PAGE
;*********************************************************
;     BCD To Binary Conversion
;
;   This routine converts a 5 digit BCD number to a 16 bit binary
; number.
;   The input 5 digit BCD numbers are asumed to be in locations
; R0, R1 & R2 with R0 containing the MSD in its right most nibble.
;
;   The 16 bit binary number is output in registers Hbyte & Lbyte
; ( high byte & low byte repectively ).
;
;   The method used for conversion is :
;     input number X = abcde ( the 5 digit BCD number )
;   X = (R0,R1,R2) = abcde = 10[10[10[10a+b]+c]+d]+e
;
; Performance :
;     Program Memory:30
;     Clock Cycles  :112
;
;***********************************************;
;
mpy10b
andlw  0x0f
addwf Lbyte
btfsc  _carry
incf Hbyte
mpy10a
bcf  _carry    ; multiply by 2
rlcf Lbyte,w
movwf Ltemp
rlcf Hbyte,w   ; (Htemp,Ltemp) = 2*N
movwf Htemp
;
bcf  _carry    ; multiply by 2
rlcf Lbyte
rlcf Hbyte
bcf  _carry    ; multiply by 2
rlcf Lbyte
rlcf Hbyte
bcf  _carry    ; multiply by 2
rlcf Lbyte
rlcf Hbyte ; (Hbyte,Lbyte) = 8*N
;
movfp  Ltemp,wreg
addwf Lbyte
movfp  Htemp,wreg
addwfc  Hbyte
return       ; (Hbyte,Lbyte) = 10*N
;
;
BCDtoB
clrf Hbyte
movfp  R0,wreg
andlw  0x0f
movwf Lbyte
call  mpy10a    ; result = 10a+b
;
swapf  R1,w
call  mpy10b    ; result = 10[10a+b]
;
movfp  R1,wreg
call  mpy10b    ; result = 10[10[10a+b]+c]
;
swapf  R2,w
call  mpy10b    ; result = 10[10[10[10a+b]+c]+d]
;
movfp  R2,wreg
andlw  0x0f
addwf Lbyte
btfsc  _carry
incf Hbyte   ; result = 10[10[10[10a+b]+c]+d]+e
return      ; BCD to binary conversion done
;
PAGE
;***********************************************;
;
;     Unsigned BCD Addition
;
;   This routine performs a 2 Digit Unsigned BCD Addition
; It is assumed that the two BCD numbers to be added are in
; locations Num1 & Num2. The result is the sum of Num1+Num2
; and is stored in location Num2 and the overflow carry is returned
; in location Num1
;
; Performance :
;     Program Memory:   5
;     Clock Cycles  :   5
;
;*****************************************;
;
BCDAdd
movfp  Num1,wreg
addwf Num2,w    ; perform binary addition
daw Num2  ; adjust for BCD addition
clrf Num1
rlcf Num1  ; set Num1 = carry bit
return
;
;******************************************************
;
END